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Economy riddle

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Date Editor Before After
8/21/2021 12:28:36 PMUSrankAdminSteel_Blue before revert after revert
10/8/2018 4:32:58 AMUSrankAdminSteel_Blue before revert after revert
10/7/2018 6:36:12 PMUSrankAdminSteel_Blue before revert after revert
10/7/2018 6:17:31 PMUSrankAdminSteel_Blue before revert after revert
Before After
1 [url=https://zero-k.info/Battles/Detail/1180196]EDIT: Zero-K v1.9.8.0 demo[/url]
2 \n
1 Say you're playing on a map where the mexes all give 2.0 metal/s. 3 Say you're playing on a map where the mexes all give 2.0 metal/s.
2 \n 4 \n
3 you have 10 metal extractors and 14 solar collectors, your com is alive, the 14 solar collectors are connected in a grid with 2 mexes and 8 mexes are not in grid. 5 you have 10 metal extractors and 14 solar collectors, your com is alive, the 14 solar collectors are connected in a grid with 2 mexes and 8 mexes are not in grid.
4 \n 6 \n
5 you have 9 metal extractors and 14 solar collectors, your com is alive, with a much more complicated grid. 7 solars are connected in a grid with 2 mexes, 3 solars connect a grid of 2 mexes, 1 solar connects a grid of 2 close mexes, there are 2 cases of a mex connected to a single solar and a single lone mex. 7 you have 9 metal extractors and 14 solar collectors, your com is alive, with a much more complicated grid. 7 solars are connected in a grid with 2 mexes, 3 solars connect a grid of 2 mexes, 1 solar connects a grid of 2 close mexes, there are 2 cases of a mex connected to a single solar and a single lone mex.
6 \n 8 \n
7 Ignoring any threat of enemies and assuming you are spending all the metal you produce into a detriment assisted by 50 build power(or any number more than your income), and your energy is at max storage, which scenario will produce the detriment the fastest? 9 Ignoring any threat of enemies and assuming you are spending all the metal you produce into a detriment assisted by 50 build power(or any number more than your income), and your energy is at max storage, which scenario will produce the detriment the fastest?
8 \n 10 \n
9 Solution: 11 Solution:
10 [spoiler] 12 [spoiler]
11 It's a trick question! 13 It's a trick question!
12 https://www.youtube.com/watch?v=aE5EzFD9z7o 14 https://www.youtube.com/watch?v=aE5EzFD9z7o
13 \n 15 \n
14 9 mxes 14 solars vs 10 mexes 14 solars. 16 9 mxes 14 solars vs 10 mexes 14 solars.
15 \n 17 \n
16 the grids I gave in the post are very confusing, but what it amounts to is in the 9 mex sinario 8 mexes have access to 1 energy in it's grid, and in the 10 mex scenario 2 mexes have access to 4 energy in their grids. 18 the grids I gave in the post are very confusing, but what it amounts to is in the 9 mex sinario 8 mexes have access to 1 energy in it's grid, and in the 10 mex scenario 2 mexes have access to 4 energy in their grids.
17 \n 19 \n
18 But wait! what you're saying is that both scenarios have only 8 excess energy, but when you look at the math it's actually 10 excess energy and 12 excess energy! The answer to that is confusing, isn't it? if all the excess energy were converted to metal, you would not have any energy to SPEND that metal. what this means is that the excess energy is separated into 2 sections, the energy spent to overdrive into metal, and the energy saved to spend that metal. And these values end up equivalent, where the metal value of the energy for overdrive equals the energy value left over. 20 But wait! what you're saying is that both scenarios have only 8 excess energy, but when you look at the math it's actually 10 excess energy and 12 excess energy! The answer to that is confusing, isn't it? if all the excess energy were converted to metal, you would not have any energy to SPEND that metal. what this means is that the excess energy is separated into 2 sections, the energy spent to overdrive into metal, and the energy saved to spend that metal. And these values end up equivalent, where the metal value of the energy for overdrive equals the energy value left over.
19 \n 21 \n
20 Here's a good time to remind you the formula for overdrive. 22 Here's a good time to remind you the formula for overdrive.
21 overdrive% = (sqrt(energy into mex)/4)*100% 23 overdrive% = (sqrt(energy into mex)/4)*100%
22 that's a lot to unpack, so here are some simpler values to remember: 24 that's a lot to unpack, so here are some simpler values to remember:
23 1e =25% overdrive 25 1e =25% overdrive
24 4e = 50% overdrive 26 4e = 50% overdrive
25 9e = 75% overdrive 27 9e = 75% overdrive
26 16e = 100% overdrive 28 16e = 100% overdrive
27 64e = 200% overdrive 29 64e = 200% overdrive
28 256e = 300% overdrive 30 256e = 300% overdrive
29 having the first 2 key values is important to us. so let's go back to the problem. 31 having the first 2 key values is important to us. so let's go back to the problem.
30 \n 32 \n
31 in case 9 mexes, you have 12 excess energy. take my word for it, split that into 8 overdrive energy and 4 spend energy. The grids are confusing, but the energy can be evenly distributed to all 8 mexes at 1e/mex, and that translates to 25% of 2 or 0.5 m/e. 8*0.5=4, equal to our spend energy, so 12 excess energy converts to 4 spendable metal in overdrive. 33 in case 9 mexes, you have 12 excess energy. take my word for it, split that into 8 overdrive energy and 4 spend energy. The grids are confusing, but the energy can be evenly distributed to all 8 mexes at 1e/mex, and that translates to 25% of 2 or 0.5 m/e. 8*0.5=4, equal to our spend energy, so 12 excess energy converts to 4 spendable metal in overdrive.
32 \n 34 \n
33 Note that the 2 caretakers and strider hub produce .9 metal and energy. 35 Note that the 2 caretakers and strider hub produce .9 metal and energy.
34 \n 36 \n
35 in case 10 mexes, you have 10 excess energy. only 2 mexes are in grid, so we can only overdrive those 2 mexes. split the energy into 8 overdrive energy and 2 spend energy. the 8 OD energy goes 4e per mex. that's 50% overdrive on a 2.0 mex, or 0.25m/e. .25*8= 2 metal, equal to our spend energy. In this set up, the 10 excess energy converted into 2 usable metal in overdrive. 37 in case 10 mexes, you have 10 excess energy. only 2 mexes are in grid, so we can only overdrive those 2 mexes. split the energy into 8 overdrive energy and 2 spend energy. the 8 OD energy goes 4e per mex. that's 50% overdrive on a 2.0 mex, or 0.25m/e. .25*8= 2 metal, equal to our spend energy. In this set up, the 10 excess energy converted into 2 usable metal in overdrive.
36 \n 38 \n
37 so, calculating the sum total of everything: 39 so, calculating the sum total of everything:
38 9 mex scenario, you have 22 metal base and 34 energy, excess energy converts into 4 metal for 26 total metal. 40 9 mex scenario, you have 22 metal base and 34 energy, excess energy converts into 4 metal for 26 total metal.
39 10 mex scenario, you have 24 metal base and 34 energy, excess energy converts into 2 metal for 26 total metal. 41 10 mex scenario, you have 24 metal base and 34 energy, excess energy converts into 2 metal for 26 total metal.
40 \n 42 \n
41 So the answer is that it's a trick question, production is the same and the detriments come out at the same time! silly lobsters, building detriments. Why don't you build a paladin in half the time and win the game? 43 So the answer is that it's a trick question, production is the same and the detriments come out at the same time! silly lobsters, building detriments. Why don't you build a paladin in half the time and win the game?
42 [/spoiler] 44 [/spoiler]