| 3 | It's a trick question! Haha, got you! with careful overdrive grids, the 9 mex scenario makes up that 2 m/s! | 3 | It's a trick question! Haha, got you! with careful overdrive grids, the 9 mex scenario makes up that 2 m/s! | 
                
                    | 5 | cathartes 
            and 
            Rhade 
            did 
            an 
            attempt 
            at 
            solving 
            it 
            in 
            this 
            thread,
             
            good 
            on 
            you! 
            But,
             
            cathartes 
            overlooked 
            a 
            key 
            problem,
             
            if 
            you 
            overdrive 
            all 
            the 
            excess 
            energy 
            to 
            metal,
             
            you 
            have 
            no 
            energy 
            to 
            SPEND 
            that 
            metal.
             
            Going 
            over 
            the 
            scenarios 
            again 
            but 
            only 
            overdriving 
            8 
            energy 
            each,
             
            you 
            get 
            much 
            cleaner 
            numbers.
             
            In 
            10 
            mex 
            scenario,
             
            8e 
            = 
            4e/mex 
            * 
            2mex 
            then 
            2(
            4e 
            = 
            50%OD)
             
            = 
            2 
            * 
            1 
            = 
            2m,
             
            and 
            you 
            can 
            spend 
            that 
            2m 
            with 
            the 
            left 
            over 
            2 
            energy.
             
            In 
            the 
            9 
            mex 
            scenario,
             
            split 
            12 
            excess 
            e 
            into 
            8 
            and 
            4,
             
            8e 
            = 
            1e/mex 
            *8mex 
            then 
            we 
            get 
            8(
            1e 
            = 
            25%OD)
             
            = 
            8 
            * 
            .
            5 
            = 
            4 
            metal.
             
            the 
            4 
            metal 
            can 
            be 
            spent 
            with 
            that 
            4 
            energy 
            I 
            reserved 
            from 
            earlier.
            the 
            9 
            mex 
            scenario 
            generates 
            an 
            extra 
            2m/s,
             
            gapping 
            the 
            bridge 
            between 
            the 
            mex 
            difference 
            generating 
            the 
            same 
            income. | 5 | cathartes 
            and 
            Rhade 
            did 
            an 
            attempt 
            at 
            solving 
            it 
            in 
            this 
            thread,
             
            good 
            on 
            you! 
            But,
             
            cathartes 
            overlooked 
            a 
            key 
            problem,
             
            if 
            you 
            overdrive 
            all 
            the 
            excess 
            energy 
            to 
            metal,
             
            you 
            have 
            no 
            energy 
            to 
            SPEND 
            that 
            metal.
             
            Going 
            over 
            the 
            scenarios 
            again 
            but 
            only 
            overdriving 
            8 
            energy 
            each,
             
            you 
            get 
            much 
            cleaner 
            numbers.
             
            In 
            10 
            mex 
            scenario,
             
            8e= 
            4e/mex 
            * 
            2mex 
            then 
            2(
            4e= 
            50%OD)
            = 
            2 
            * 
            1= 
            2m,
             
            and 
            you 
            can 
            spend 
            that 
            2m 
            with 
            the 
            left 
            over 
            2 
            energy.
             
            In 
            the 
            9 
            mex 
            scenario,
             
            split 
            12 
            excess 
            e 
            into 
            8 
            and 
            4,
             
            8e= 
            1e/mex 
            *8mex 
            then 
            we 
            get 
            8(
            1e= 
            25%OD)
            = 
            8 
            * 
            .
            5= 
            4 
            metal.
             
            the 
            4 
            metal 
            can 
            be 
            spent 
            with 
            that 
            4 
            energy 
            I 
            reserved 
            from 
            earlier.
            the 
            9 
            mex 
            scenario 
            generates 
            an 
            extra 
            2m/s,
             
            gapping 
            the 
            bridge 
            between 
            the 
            mex 
            difference 
            generating 
            the 
            same 
            income. |