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[quote]Zero-K 1.10.6.0 Terra 2 (5+1/32) 7 hours ago:
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[quote]Zero-K 1.10.6.0 Terra 2 (5+1/32) 7 hours ago:
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4 players balanced Normal to 2 teams ( ( 1=71%) : 2=29%)). 4 combinations checked, spent 0ms of CPU time[/quote]
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4 players balanced Normal to 2 teams ( ( 1=71%) : 2=29%)). 4 combinations checked, spent 0ms of CPU time[/quote]
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[quote]Zero-K 1.10.6.0 Into Battle v4 (9+5/32) 5 hours ago:
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[quote]Zero-K 1.10.6.0 Into Battle v4 (9+5/32) 5 hours ago:
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8 players balanced ClanWise to 2 teams ( ( 1=52%) : 2=48%)). 16 combinations checked, spent 0ms of CPU time[/quote]
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8 players balanced ClanWise to 2 teams ( ( 1=52%) : 2=48%)). 16 combinations checked, spent 0ms of CPU time[/quote]
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If the number of players in the room is large, the balancer will almost always manage to find teams with very nearly equal rating average, so you will almost always see 50% or occasionally perhaps 51% in large teams.
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If the number of players in the room is large, the balancer will almost always manage to find teams with very nearly equal rating average, so you will almost always see 50% or occasionally perhaps 51% in large teams.
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(
Broadly
speaking,
this
is
because
(
a)
the
number
of
potential
team
assignments
increases
exponentially,
and
(
b)
even
a
randomly
selected
team
assignment
is
increasingly
likely
to
be
pretty
close
to
balanced
as
the
number
of
players
increases.
Law
of
large
numbers
and
all
that.
)
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7 |
(
Broadly
speaking,
this
is
because
(
a)
the
number
of
potential
team
assignments
increases
exponentially,
and
(
b)
even
a
randomly
selected
team
assignment
is
increasingly
likely
to
be
pretty
close
to
balanced
as
the
number
of
players
increases.
)
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8 |
\n
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8 |
\n
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9 |
If I remember the code correctly, the "empty" player is assumed to have rating equal to the average rating of all players in the room. Perhaps it should count for less than that. I am not sure if anybody has run the numbers to figure that out.
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9 |
If I remember the code correctly, the "empty" player is assumed to have rating equal to the average rating of all players in the room. Perhaps it should count for less than that. I am not sure if anybody has run the numbers to figure that out.
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